Complete reduction of 1 mole of (3E,5Z)-3-methylhepta-3,5-dien-1-yne will require how many moles of hydrogen (H₂)? A) 1 B) 2 C) 3 D) 4 E) 5

Name: Complete reduction of 1 mole of (3E,5Z)-3-methylhepta-3,5-dien-1-yne will require how many moles of hydrogen (H 2 )? A) 1 B) 2 C) 3 D) 4 E) 5
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Question

Quizplus · Accepted Answer

The molecule has 3 double bonds and 1 triple bond. Each double bond requires 1 mole of hydrogen to reduce, and the triple bond requires 2 moles of hydrogen. Therefore, 3 + 2 = 5 moles of hydrogen are needed in total.

Complete Reduction of 1 Mole of (3E,5Z)-3-Methylhepta-3,5-Dien-1-Yne Will Require How