In a given population of individuals with a particular gene of interest, the allele frequencies for that gene are equal (there are only two alleles for this gene: A and a). What are the expected genotype frequencies, assuming the population is in Hardy-Weinberg equilibrium?
A)AA = 0.5, aa = 0.5
B)AA = 0.25, Aa = 0.50, aa = 0.25
C)The answer cannot be determined because the allele frequencies are not provided.

Question

Quizplus · Accepted Answer

In Hardy-Weinberg equilibrium, the expected genotype frequencies can be calculated using the equation p^2 + 2pq + q^2 = 1, where p and q are the frequencies of the A and a alleles, respectively. If the allele frequencies are equal, then p = q = 0.5. Substituting these values into the equation gives: (0.5)^2 + 2(0.5)(0.5) + (0.5)^2 = 0.25 + 0.50 + 0.25 = 1. Thus, the expected genotype frequencies are AA = 0.25, Aa = 0.50, and aa = 0.25.

In a Given Population of Individuals with a Particular Gene