What volume of 17.4 M H₂SO₄ is required to prepare 12.0 L of 0.156 M sulfuric acid? (Ignore significant figures for this problem.) A) 226 mL B) 2.71 L C) 112 mL D) 108 mL E) 1.34 L

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To prepare a dilute solution from a concentrated one, the formula $C_1V_1 = C_2V_2$ is used, where $C_1$ and $V_1$ are the concentration and volume of the concentrated solution, and $C_2$ and $V_2$ are the concentration and volume of the dilute solution. Plugging in the given values: $17.4 \, \text{M} \times V_1 = 0.156 \, \text{M} \times 12.0 \, \text{L}$. Solving for $V_1$ gives approximately 0.108 L or 108 mL.

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