A 2.0-kg block travels around a 0.50-m radius circle with an angular velocity of 12 rad/s. The magnitude of its angular momentum about the center of the circle is: A) 6.0 kg . m²/s B) 12 kg . m²/s C) 48 kg/m² . s D) 72 kg . m²/s² E) 576 kg/m² . s²

Question

Quizplus · Accepted Answer

Angular momentum is given by L = Iω, where I is the moment of inertia and ω is the angular velocity. For a point mass rotating about an axis perpendicular to its path, I = mr^2, where m is the mass and r is the distance from the axis of rotation. In this case, m = 2.0 kg, r = 0.50 m, and ω = 12 rad/s. Therefore, L = (2.0 kg)(0.50 m)^2(12 rad/s) = 6.0 kg m^2/s.

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