To store a total of 0.040 J of energy in the two identical capacitors shown, each should have a capacitance of:
A) 0.10 $\mu$F
B) 0.50 $\mu$F0.10 $\mu$F
C) 1.0 $\mu$F
D) 1.5 $\mu$F
E) 2.0 $\mu$F

Question

To store a total of 0.040 J of energy in the two identical capacitors shown, each should have a capacitance of: 
A) 0.10 $\mu$F 
B) 0.50 $\mu$F0.10 $\mu$F 
C) 1.0 $\mu$F 
D) 1.5 $\mu$F 
E) 2.0 $\mu$F

Quizplus · Accepted Answer

The energy stored in a capacitor is given by the formula: E = (1/2)CV^2, where E is the energy, C is the capacitance, and V is the voltage across the capacitor.

Since the capacitors are identical, they will have the same capacitance. Let the capacitance be C.

The total energy stored in the capacitors is given as 0.040 J.

So, E = (1/2)CV^2 = 0.040 J

Solving for C, we get C = (2E/V^2) = (2*0.040)/(50^2) = 1.6*10^-5 F = 1.6 μF (approx.)

The closest capacitance value given in the options is 1.0 μF, which is the best choice.

To Store a Total of 0 μ\muμ F B) 0 μ\muμ F010 μ\muμ

To Store a Total of 0 $\mu$ F
B) 0 $\mu$ F010 $\mu$