A nucleus with mass number A and atomic number Z undergoes $\beta$⁺ decay. The mass number and atomic number, respectively, of the daughter nucleus are: A) A - 1, Z - 1 B) A - 1, Z + 1 C) A + 1, Z - 1 D) A, Z + 1 E) A, Z - 1

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The Answer of A nucleus with mass number A and atomic number Z undergoes $\beta$⁺ decay. The mass number and atomic number, respectively, of the daughter nucleus are: A) A - 1, Z - 1 B) A - 1, Z + 1 C) A + 1, Z - 1 D) A, Z + 1 E) A, Z - 1

A Nucleus with Mass Number a and Atomic Number Z β\betaβ

A Nucleus with Mass Number a and Atomic Number Z $\beta$