The volume of a gas with an initial pressure of 380 mmHg atm increases from 5.0 L to 8.0 L. What is the final pressure of the gas,in atm, assuming no change in moles or temperature?
A)238 atm
B)2.4 atm
C)0.31 atm
D)0.80 atm
E)8.0 atm

Question

Quizplus · Accepted Answer

Using Boyle's Law (P1V1 = P2V2), where P1 = 380 mmHg, V1 = 5.0 L, V2 = 8.0 L, we solve for P2: P2 = (P1V1)/V2 = (380 mmHg * 5.0 L) / 8.0 L = 237.5 mmHg. Converting to atm: 237.5 mmHg * (1 atm / 760 mmHg) ≈ 0.31 atm.

The Volume of a Gas with an Initial Pressure of 380