Given that the K_a for HOCl is 3.5 × 10^-8, calculate the K value for the reaction of HOCl with OH^-. A) 3.5 × 10^-22 B) 3.5 × 10^-8 C) 2.9 × 10^-7 D) 3.5 × 10⁶ E) none of these

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Quizplus · Accepted Answer

The reaction of HOCl with OH⁻ is the reverse of the dissociation of HOCl. The equilibrium constant for the reverse reaction is K = 1/Kw * Ka, where Kw is the ion product of water (1.0 × 10⁻¹⁴). Thus, K = 1/(1.0 × 10⁻¹⁴) * (3.5 × 10⁻⁸) = 3.5 × 10⁶.

Given That the Ka for HOCl Is 3

Given That the K_a for HOCl Is 3