What is the molarity of a sodium hydroxide solution if 25.0 mL of this solution reacts exactly with 22.30 mL of 0.253 M sulfuric acid?
A) 0.284 M
B) 0.451 M
C) 0.567 M
D) 0.226 M
E) 0.113 M

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is: 2 NaOH + H2SO4 → Na2SO4 + 2 H2O. This shows that 2 moles of NaOH react with 1 mole of H2SO4. Using the molarity and volume of H2SO4, calculate moles of H2SO4: 0.253 M * 0.0223 L = 0.0056419 moles. Since the ratio is 2:1, moles of NaOH = 2 * 0.0056419 = 0.0112838 moles. Molarity of NaOH = moles/volume in liters = 0.0112838 moles / 0.025 L = 0.451 M.

What Is the Molarity of a Sodium Hydroxide Solution If