Substance X has a heat of vaporization of 55.4 kJ/mol at its normal boiling point (423°C). For the process X(l) → X(g) at 1 atm and 423°C, calculate the value of:
-Consider the freezing of liquid water at -10°C. For this process what are the signs for ΔH, ΔS, and ΔG, respectively?

Question

Quizplus · Accepted Answer

For the freezing of liquid water, ΔH is negative because heat is released. ΔS is negative because the system becomes more ordered. ΔG is negative because the process is spontaneous at temperatures below 0°C.

Substance X Has a Heat of Vaporization of 55