What is the molality of a solution of 39.8 g of ethanol (CH₃CH₂OH) in 441 mL of water if the density of water is 1.0 g/mL? A) 90.2 m B) 1.80 m C) 1.96 m D) 0.0341 m E) 0.0353 m

Question

Quizplus · Accepted Answer

First, we need to convert the mass of ethanol to moles:
39.8 g / 46.07 g/mol = 0.864 mol
Next, we need to convert the volume of water to mass:
441 mL x 1.0 g/mL = 441 g
We now have the necessary information to calculate molality, which is defined as moles of solute per kilogram of solvent:
molality = 0.864 mol / 0.441 kg = 1.96 m

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