A briefcase 4.5 in × 22 in × 11 in is filled with gold, which has a density of 19.3 g/cm3 and costs $308/oz. What is the mass of this gold in kg?
A) 460 kg
B) 53.5 kg
C) 136 kg
D) 344 kg
E) 17.9 kg

Question

Quizplus · Accepted Answer

First, we need to convert the dimensions of the briefcase to cm: 11 in = 27.94 cm, 22 in = 55.88 cm, 4.5 in = 11.43 cm.

Next, we can use the formula for volume: V = l × w × h.

V = (27.94 cm) × (55.88 cm) × (11.43 cm) = 17,748 cm^3.

To find the mass, we need to multiply the volume by the density of gold:

m = V × ρ = 17,748 cm^3 × 19.3 g/cm^3 = 342,308.4 g = 342.31 kg.

Finally, we can multiply the mass by the cost per ounce to find the total cost:

cost = m × (1 oz / 28.35 g) × $308/oz = $341,142.32.

Therefore, the answer is D) 344 kg.

A Briefcase 4