Write the net ionic equation for the reaction of lead(II) nitrate and sodium iodide. A) Pb(NO₃)₂(aq) + 2NaI(aq) → PbI₂(s) + 2 NaNO₃(aq) B) Pb²⁺ + 2 NaI(aq) → PbI₂(s) + 2 Na C) Pb²⁺ + 2 I- → PbI₂(s) D) Pb²⁺ + 2 I- → Pb²⁺ + 2 I- E) no reaction

Question

Quizplus · Accepted Answer

The net ionic equation shows only the species that are directly involved in the reaction and undergo a change in oxidation state or state of matter. In this case, the lead(II) ion and iodide ion react to form solid lead(II) iodide. The spectator ions, sodium and nitrate, remain unchanged and are not included in the net ionic equation. The correct net ionic equation is Pb2+(aq) + 2I-(aq) → PbI2(s). Choice A has incorrect formulas for lead nitrate and sodium iodide, and includes the spectator ions. Choice B does not show the correct products of the reaction. Choice D shows no reaction occurring, which is incorrect.

Write the Net Ionic Equation for the Reaction of Lead(II)