A 500.0 mL sample of O₂(g) is at 780 mmHg and 30°C. What will be the new volume if, with constant pressure and amount of gas, the temperature is decreased to -15°C?

Question

Quizplus · Accepted Answer

First, we need to convert the initial pressure to atm:

780 mmHg x (1 atm / 760 mmHg) = 1.03 atm

Next, we can use the combined gas law:

(P1V1/T1) = (P2V2/T2)

We know that the pressure and amount of gas are constant, so we can simplify the equation:

V1/T1 = V2/T2

Now we can plug in the values we know:

(500.0 mL)/(30°C + 273) = V2/(-15°C + 273)

Solving for V2:

V2 = (500.0 mL)(-15°C + 273)/(30°C + 273) = 426 mL

Therefore, the new volume is 426 mL.

A 5000 ML Sample of O2(g) Is at 780 MmHg and and 30°C

A 5000 ML Sample of O₂(g) Is at 780 MmHg and and 30°C