A researcher records the following number of birdcalls made during an experimental session with robins: 7.2 0.6 (M SD).Assuming these data are normally distributed,what is the probability that robins made more than 9 birdcalls during this experimental session?
A).9987
B).4987
C).0013
D)The probability is not listed in the unit normal table.

Question

A researcher records the following number of birdcalls made during an experimental session with robins: 7.2  0.6 (M  SD).Assuming these data are normally distributed,what is the probability that robins made more than 9 birdcalls during this experimental session?
A).9987 
B).4987 
C).0013 
D)The probability is not listed in the unit normal table.

Quizplus · Accepted Answer

First, we need to standardize the data to convert it to a standard normal distribution. We can do this using the formula:

z = (x - μ) / σ

where z is the standard score, x is the observed value, μ is the mean, and σ is the standard deviation.

In this case:

z = (9 - 7.2) / 0.6 = 3

Using a standard normal table or calculator, we can find that the probability of z being greater than 3 is approximately 0.0013. Therefore, the probability that robins made more than 9 birdcalls during this experimental session is 0.0013 or 0.13%.

The correct answer is C).

A Researcher Records the Following Number of Birdcalls Made During