A 10-kilogram block with an initial velocity of 10 m/s slides 10 meters across a horizontal surface and comes to rest.It takes the block 2 seconds to stop.The stopping force acting on the block is about
A)5 N.
B)10 N.
C)25 N.
D)50 N.
E)none of these

Question

Quizplus · Accepted Answer

The stopping force can be calculated using the formula F = ma, where m is mass and a is acceleration. First, find the acceleration using the formula a = (v_f - v_i) / t, where v_f is final velocity (0 m/s), v_i is initial velocity (10 m/s), and t is time (2 s). This gives a = -5 m/s². Then, F = 10 kg * (-5 m/s²) = -50 N. The magnitude of the force is 50 N.

A 10-Kilogram Block with an Initial Velocity of 10 M/s