If f (-1) = 3 and $f ^ { \prime } ( - 1 ) = 2$ , find an equation of the tangent line at x = -1.
A)y = -5 + 2x
B)y = 1 + 2x
C)y = -2x + 1
D)y = 5 - 2x
E)y = -1 + 2x
F)y = 5 + 2x
G)Does not exist
H)None of the above

Question

Quizplus · Accepted Answer

The equation of the tangent line at a point is given by $y = f(a) + f'(a)(x - a)$. Here, $a = -1$, $f(-1) = 3$, and $f'(-1) = 2$. So, the equation is $y = 3 + 2(x + 1)$, which simplifies to $y = 5 + 2x$.

If F (-1) = 3 And f′(−1)=2f ^ { \prime } ( - 1 ) = 2f′(−1)=2

If F (-1) = 3 And $f ^ { \prime } ( - 1 ) = 2$