Use Definition 2 to show that the area under the curve $y = x ^ { 3 } , 0 \leq x \leq 1 \text { is } \frac { 1 } { 4 }$ Recall that $\sum _ { k = 1 } ^ { n } k ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 }$

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The Answer of Use Definition 2 to show that the area under the curve $y = x ^ { 3 } , 0 \leq x \leq 1 \text { is } \frac { 1 } { 4 }$ Recall that $\sum _ { k = 1 } ^ { n } k ^ { 3 } = \frac { n ^ { 2 } ( n + 1 ) ^ { 2 } } { 4 }$

Use Definition 2 to Show That the Area Under the Curve