If $\frac { 3 n - 1 } { n + 1 }

Name: If $\frac { 3 n - 1 } { n + 1 } < x _ { n } < \frac { 3 n ^ { 2 } + 6 n + 2 } { n ^ { 2 } + 2 n + 1 }$ for all positive integers n, then find $\lim _ { n \rightarrow \infty } x _ { n }$ .
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Question

If $\frac { 3 n - 1 } { n + 1 } < x _ { n } < \frac { 3 n ^ { 2 } + 6 n + 2 } { n ^ { 2 } + 2 n + 1 }$ for all positive integers n, then find $\lim _ { n \rightarrow \infty } x _ { n }$ .

Quizplus · Accepted Answer

The Answer of If $\frac { 3 n - 1 } { n + 1 } < x _ { n } < \frac { 3 n ^ { 2 } + 6 n + 2 } { n ^ { 2 } + 2 n + 1 }$ for all positive integers n, then find $\lim _ { n \rightarrow \infty } x _ { n }$ .

If 3n−1n+1<xn<3n2+6n+2n2+2n+1\frac { 3 n - 1 } { n + 1 } < x _ { n } < \frac { 3 n ^ { 2 } + 6 n + 2 } { n ^ { 2 } + 2 n + 1 }n+13n−1​<xn​<n2+2n+13n2+6n+2​

If $\frac { 3 n - 1 } { n + 1 } < x _ { n } < \frac { 3 n ^ { 2 } + 6 n + 2 } { n ^ { 2 } + 2 n + 1 }$