Arrange the following Group 2A elements (in their ionic form)from largest to smallest atomic radius. A)Ra²⁺ Ba²⁺ Sr²⁺ Ca²⁺ Mg²⁺ B)Sr²⁺ Ca²⁺ Ba²⁺ Mg²⁺ Ra²⁺ C)Ba²⁺ Ra²⁺ Ca²⁺ Sr²⁺ Mg²⁺ D)Mg²⁺ Ca²⁺ Sr²⁺ Ba²⁺ Ra²⁺ E)Ra²⁺ Mg²⁺ Ba²⁺ Ca²⁺ Sr²⁺

Question

Arrange the following Group 2A elements (in their ionic form)from largest to smallest atomic radius. A)Ra²⁺ > Ba²⁺ > Sr²⁺ > Ca²⁺ > Mg²⁺ B)Sr²⁺ > Ca²⁺ > Ba²⁺ > Mg²⁺ > Ra²⁺ C)Ba²⁺ > Ra²⁺ > Ca²⁺ > Sr²⁺ > Mg²⁺ D)Mg²⁺ > Ca²⁺ > Sr²⁺ > Ba²⁺ > Ra²⁺ E)Ra²⁺ > Mg²⁺ > Ba²⁺ > Ca²⁺ > Sr²⁺

Quizplus · Accepted Answer

In the periodic table, as you move down a group, the atomic radius increases due to the addition of electron shells. Therefore, Ra^2+ has the largest atomic radius, followed by Ba^2+, Sr^2+, Ca^2+, and Mg^2+ has the smallest atomic radius among the given ions.

Arrange the Following Group 2A Elements (In Their Ionic Form)from