Calculate the total number of unpaired electrons in the following complex ions: Zn(OH₂)₆²⁺,Ni(CN)₄²^- (square planar),Co(NH₃)₆³⁺ (strong field). A)0 B)1 C)2 D)3 E)4

Question

Quizplus · Accepted Answer

For Zn^2+ in [Zn(OH)4]^2-, Zn has a 3d^10 configuration with no unpaired electrons. For Ni^2+ in [Ni(CN)4]^2- (square planar), the strong field ligand CN^- causes pairing of electrons, resulting in no unpaired electrons. For Co^3+ in [Co(NH3)6]^3+ (strong field), the strong field ligand NH3 causes pairing of electrons, also resulting in no unpaired electrons.

Calculate the Total Number of Unpaired Electrons in the Following