If I = 2.0 mA and the potential difference,V_A - V_B = +30 V in the circuit segment shown,determine the charge and polarity of the capacitor. A)1.5 mC,left plate is positive B)1.5 mC,right plate is positive C)0.50 mC,left plate is positive D)0.50 mC,right plate is positive

Question

Quizplus · Accepted Answer

According to Kirchoff's Current Law, the current flowing into node A is equal to the current flowing out of node A. Therefore, the current through the capacitor is also 2.0 mA.

Since the potential difference across the capacitor is positive, the left plate must be at a higher potential than the right plate. This means that the left plate is positive and the right plate is negative.

Using the formula Q = CV, where Q is the charge on the capacitor, C is the capacitance, and V is the potential difference across the capacitor, we can solve for Q:

Q = CV = (4.7 µF)(30 V) = 1.41 mC

Therefore, the charge on the capacitor is 1.41 mC, which is closest to 1.5 mC (answer choice A).

If I = 20 MA and the Potential Difference,VA - VB = +30

If I = 20 MA and the Potential Difference,V_A - V_B = +30