A rectangular loop (area = 0.15 m²)turns in a uniform magnetic field with B = 0.20 T.At an instant when the angle between the magnetic field and the normal to the plane of the loop is p/2 rads and increasing at the rate of 0.60 rad/s,what is the magnitude of the emf induced in the loop? A)24 mV B)zero C)18 mV D)30 mV

Question

Quizplus · Accepted Answer

The emf induced in the loop is given by Faraday's Law of Electromagnetic Induction, which states that the emf induced is equal to the rate of change of magnetic flux through the loop.

In this case, the magnetic field is uniform and the angle between the field and the normal to the plane of the loop is changing at a constant rate of 0.60 rad/s. Thus, the magnetic flux through the loop is changing at a constant rate.

The magnitude of the emf induced in the loop is given by: 
emf = -d(phi)/dt

where phi is the magnetic flux through the loop.

The magnetic flux through the loop is given by:

phi = B*A*cos(theta)

where B is the magnetic field, A is the area of the loop, and theta is the angle between the magnetic field and the normal to the plane of the loop.

At the instant when theta = pi/2, we have:

phi = B*A*cos(pi/2) = 0

Thus, the emf induced in the loop is zero at this instant.

Therefore, the correct answer is B) zero.

A Rectangular Loop (Area = 0