An object moves by an observer at 0.500 c (1/2 the speed of light).The total energy of the object will be what factor times that of the rest energy?
A)0.600
B)0.970
C)1.15
D)1.67

Question

Quizplus · Accepted Answer

The total energy of an object moving at a velocity v is given by E = γmc², where γ = 1/√(1-v²/c²). For v = 0.500c, γ = 1/√(1-(0.500)²) = 1.15. Thus, the total energy is 1.15 times the rest energy.

An Object Moves by an Observer at 0