Calculate the range of the force that might be produced by the virtual exchange of a proton.Assume DE*Dt = h/2p.(m_p = 1.67 x 10^-27 kg,c = 3.00 x 10⁸ m/s,and h/2p = 1.05 x 10^-34 J*s) A)6.7 x 10^-25 m B)2.1 x 10^-16 m C)6.0 x 10^-8 m D)1.5 x 10^-15 m

Question

Quizplus · Accepted Answer

Using the given equation, we can calculate the range of force as follows:
DEF1F1F1S1F1F1F10 = h/2p * (1/4pε) * (q1q2/r^2)
Simplifying, we get:
r = q1q2 / (4pεDEF1F1F1S1F1F1F10)
Substituting the given values, we get:
r = (1.6 x 10^-19 C)^2 / (4p x 8.85 x 10^-12 C^2/Nm^2 x 1.05 x 10^-34 J s)
r = 2.1 x 10^-16 m
Therefore, the range of force is 2.1 x 10^-16 m, which is option B.

Calculate the Range of the Force That Might Be Produced