A block of mass 5.00 kg rests on a horizontal surface where the coefficient of kinetic friction between the two is 0.200.A string attached to the block is pulled horizontally,resulting in a 2.00-m/s² acceleration by the block.Find the tension in the string.(g = 9.80 m/s²) A)0.200 N B)9.80 N C)19.8 N D)10.0 N

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Quizplus · Accepted Answer

The tension in the string can be found using Newton's second law: T - f_k = ma, where f_k is the kinetic friction force. f_k = μ_k * N = μ_k * mg = 0.200 * 5.00 kg * 9.80 m/s² = 9.8 N. Therefore, T = ma + f_k = 5.00 kg * 2.00 m/s² + 9.8 N = 10.0 N + 9.8 N = 19.8 N.

A Block of Mass 5