The net force acting on a 6.0-kg object is given by F_x = (10 - x)N,where F_x is in newtons and x is in meters.How much work is done on the object as it moves from x = 0 to x = 10 m? A)100 J B)75 J C)50 J D)25 J

Question

Quizplus · Accepted Answer

The work done is equal to the area under the force vs distance graph. 
So, work = ∫(10-x)dx within limits from 0 to 10.
 
∫(10-x)dx = [10x - 0.5x^2] within limits from 0 to 10
 
= [10(10) - 0.5(10)^2] - [10(0) - 0.5(0)^2]
 
= 50 J. 
 
Therefore, the answer is (C) 50 J.

The Net Force Acting on a 6