Consider this operator overloading for class Money,modified from Display 8.1 by omitting the const modifier on the return type:
Money operator+(const Money& amt1,const Money& amt2);
Is the following expression legal? If legal,what could it mean,and where does the information that is assigned go?
Money m1(17.99),m2(23.57)m3(15,22);
(m1 + m2)= m3;

Question

Quizplus · Accepted Answer

The expression is legal. It means that the value of m3 is assigned to the sum of m1 and m2, which is computed by the overloaded + operator. However, since the return type of the operator+ function is not declared as const, it is possible to assign a new value to the result of the expression. This may not be desirable behavior in some cases.

Consider This Operator Overloading for Class Money,modified from Display 8