25.0 mL of 0.212 M NaOH is neutralized by 13.6 mL of an HCl solution.The molarity of the HCl solution is ________.
A)0.212 M
B)0.115 M
C)0.500 M
D)0.390 M
E)0.137 M

Question

Quizplus · Accepted Answer

Before we can find the molarity of the HCl solution, we need to calculate the number of moles of NaOH used in the reaction.

moles NaOH = M x L
moles NaOH = 0.212 M x 0.0250 L
moles NaOH = 0.00530 mol

Since NaOH and HCl react in a 1:1 mole ratio, there must be 0.00530 moles of HCl in the 13.6 mL solution.

Now we can find the molarity of the HCl solution:

Molarity = moles HCl / liters of solution

To find the liters of solution, we need to convert the volume of HCl solution from milliliters to liters:

13.6 mL = 0.0136 L

Molarity = 0.00530 mol / 0.0136 L
Molarity = 0.389 M

Therefore, the molarity of the HCl solution is 0.390 M, which is closest to choice (D).

250 ML of 0