For the following question(s),consider the following balanced equation. Mg 3 N 2 + 6H 2 O → 3Mg(OH) 2 + 2NH 3 -How many grams of NO are required to produce 145 g of N₂ in the following reaction? 4NH₃ + 6NO → 5N₂ + 6H₂O A)186 g B)155 g C)125 g D)129 g E)145 g

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Quizplus · Accepted Answer

To produce 145 g of N₂, calculate moles of N₂ (145 g / 28 g/mol = 5.18 mol). From the balanced equation, 6 moles of NO produce 5 moles of N₂. Thus, 5.18 mol N₂ requires (6/5) * 5.18 mol NO = 6.216 mol NO. Convert to grams: 6.216 mol * 30 g/mol = 186.48 g NO, approximately 186 g.

For the Following Question(s),consider the Following Balanced Equation