Solve the equation. $3 x ^ { 2 } - 6 x - 2 = 0$
A) $x = - 6$ ,
$x = - 4$
B) $x = 4$ ,
$x = - 6$
C) $x = 1 \pm \frac { \sqrt { 13 } } { 3 }$
D) $x = 1 \pm \frac { \sqrt { 3 } } { 3}$
E) $x = - 1 \pm \frac { 3 \sqrt { 3 } } { 3 }$

Question

Quizplus · Accepted Answer

We can solve the quadratic equation by using the quadratic formula: $x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$. In this case, $a=3$, $b=-6$, and $c=-2$. Substituting these values into the formula, we get:

$x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(3)(-2)}}{2(3)}$
$x = \frac{6 \pm \sqrt{60}}{6}$
$x = \frac{6 \pm 2\sqrt{15}}{6}$
$x = 1 \pm \frac{\sqrt{15}}{3}$

This is equivalent to choice C. Therefore, the answer is C.

Solve the Equation 3x2−6x−2=03 x ^ { 2 } - 6 x - 2 = 03x2−6x−2=0

Solve the Equation $3 x ^ { 2 } - 6 x - 2 = 0$