Find $P ( x , y )$ on the unit circle, given that the $x$ - coordinate of $P$ is $\frac { 1 } { 3 }$ and $P$ is in quadrant IV.

Name: Find $P ( x , y )$ on the unit circle, given that the $x$ - coordinate of $P$ is $\frac { 1 } { 3 }$ and $P$ is in quadrant IV.
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Question

Quizplus · Accepted Answer

The Answer is

P

is in quadrant IV, so

y

is negative.

y = - \sqrt { 1 - \left( \frac { 1 } { 3 } \right) ^ { 2 } } = - \sqrt { \frac { 8 } { 9 } } = - \frac { 2 \sqrt { 2 } } { 3 }

. So

D = \left( \frac { 1 } { 3 } , - \frac { 2 \sqrt { 2 } } {3 } \right)

.

Find P(x,y)P ( x , y )P(x,y) On the Unit Circle, Given That The

Find $P ( x , y )$ On the Unit Circle, Given That The