Two chemicals react to form another chemical. Suppose that the amount of chemical formed in time t (in hours) is given by $x(t)=\frac{11\left[1-\left(\frac{2}{3}\right)^{3 t}\right]}{1-\frac{1}{4}\left(\frac{2}{3}\right)^{3 t}}$ where $x(t)$ is measured in pounds.
a. Find the rate at which the chemical is formed when $t=4$ Round to two decimal places.
b. How many pounds of the chemical are formed eventually?

Question

Two chemicals react to form another chemical. Suppose that the amount of chemical formed in time t (in hours) is given by $x(t)=\frac{11\left[1-\left(\frac{2}{3}\right)^{3 t}\right]}{1-\frac{1}{4}\left(\frac{2}{3}\right)^{3 t}}$ where $x(t)$ is measured in pounds. 
a. Find the rate at which the chemical is formed when $t=4$ Round to two decimal places. 
b. How many pounds of the chemical are formed eventually?

Quizplus · Accepted Answer

The Answer of Two chemicals react to form another chemical. Suppose that the amount of chemical formed in time t (in hours) is given by $x(t)=\frac{11\left[1-\left(\frac{2}{3}\right)^{3 t}\right]}{1-\frac{1}{4}\left(\frac{2}{3}\right)^{3 t}}$ where $x(t)$ is measured in pounds. 
a. Find the rate at which the chemical is formed when $t=4$ Round to two decimal places. 
b. How many pounds of the chemical are formed eventually?

Two Chemicals React to Form Another Chemical x(t)=11[1−(23)3t]1−14(23)3tx(t)=\frac{11\left[1-\left(\frac{2}{3}\right)^{3 t}\right]}{1-\frac{1}{4}\left(\frac{2}{3}\right)^{3 t}}x(t)=1−41​(32​)3t11[1−(32​)3t]​ Where x(t)x(t)x(t)

Two Chemicals React to Form Another Chemical $x(t)=\frac{11\left[1-\left(\frac{2}{3}\right)^{3 t}\right]}{1-\frac{1}{4}\left(\frac{2}{3}\right)^{3 t}}$ Where $x(t)$