Evaluate the integral using an appropriate trigonometric substitution. $\int_{0}^{\sqrt{2}} \frac{x^{2}}{\sqrt{4-x^{2}}} d x$
A) $\pi$
B) $\frac{\pi}{2}-1$
C) $\frac{2 \pi}{3}-\frac{\sqrt{3}}{2}$
D) $\pi-1$

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The Answer of Evaluate the integral using an appropriate trigonometric substitution. $\int_{0}^{\sqrt{2}} \frac{x^{2}}{\sqrt{4-x^{2}}} d x$
A) $\pi$
B) $\frac{\pi}{2}-1$
C) $\frac{2 \pi}{3}-\frac{\sqrt{3}}{2}$
D) $\pi-1$

Evaluate the Integral Using an Appropriate Trigonometric Substitution ∫02x24−x2dx\int_{0}^{\sqrt{2}} \frac{x^{2}}{\sqrt{4-x^{2}}} d x∫02​​4−x2​x2​dx

Evaluate the Integral Using an Appropriate Trigonometric Substitution $\int_{0}^{\sqrt{2}} \frac{x^{2}}{\sqrt{4-x^{2}}} d x$