Determine the number of terms sufficient to obtain the sum of the series accurate to three decimal places. $\sum _ { n = 0 } ^ { \infty } \frac { ( - 4 ) ^ { n + 3 } } { ( n + 1 ) ! }$
A) 16
B) 19
C) 18
D) 17

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The Answer of Determine the number of terms sufficient to obtain the sum of the series accurate to three decimal places. $\sum _ { n = 0 } ^ { \infty } \frac { ( - 4 ) ^ { n + 3 } } { ( n + 1 ) ! }$
A) 16
B) 19
C) 18
D) 17

Determine the Number of Terms Sufficient to Obtain the Sum ∑n=0∞(−4)n+3(n+1)!\sum _ { n = 0 } ^ { \infty } \frac { ( - 4 ) ^ { n + 3 } } { ( n + 1 ) ! }∑n=0∞​(n+1)!(−4)n+3​

Determine the Number of Terms Sufficient to Obtain the Sum $\sum _ { n = 0 } ^ { \infty } \frac { ( - 4 ) ^ { n + 3 } } { ( n + 1 ) ! }$