Find the area of the region that is bounded by the given curve and lies in the specified sector. $r = 9 \sqrt { \sin 2 \theta } , 0 \leq \theta \leq \pi / 2$

Name: Find the area of the region that is bounded by the given curve and lies in the specified sector. $r = 9 \sqrt { \sin 2 \theta } , 0 \leq \theta \leq \pi / 2$
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The Answer of Find the area of the region that is bounded by the given curve and lies in the specified sector. $r = 9 \sqrt { \sin 2 \theta } , 0 \leq \theta \leq \pi / 2$

Find the Area of the Region That Is Bounded by the Given