Find an equation of the line tangent to the graph of y = 6^x+ 4 at the point (0, 5). A)y = (ln 6)x + 4 B)y = 6x+ 5 C)y = 6x+ 4 D)y = (ln 6)x + 5

Name: Find an equation of the line tangent to the graph of y = 6 x + 4 at the point (0, 5). A)y = (ln 6)x + 4 B)y = 6x + 5 C)y = 6x + 4 D)y = (ln 6)x + 5
Brand: Quizplus
Rating: 4.8 (46 reviews)

Question

Quizplus · Accepted Answer

The derivative of y = 6^x is y' = 6^x * ln(6). At x = 0, y' = ln(6). The tangent line at (0, 5) has the equation y = (ln 6)x + 5.

Find an Equation of the Line Tangent to the Graph