Find the equation of the directrix of the conic.

Question

Quizplus · Accepted Answer

The directrix of a conic with eccentricity $e$ and focus $(h,k)$ is the line perpendicular to the major axis and a distance of $\frac{1}{e}$ units away from the focus. In this case, we have $e=\frac{1}{6}$ and the focus is at $(0,0)$ (since the conic has equation $6x^2-6y^2=1$). Therefore, the directrix is a vertical line $x=\frac{1}{e}=6$. The equation of this line is $x-6=0$, which can be written as $11eaa3e5\_5519\_be05\_9f8f\_8fca8e7ccde7\_TB5971\_11$.

Find the Equation of the Directrix of the Conic