The solutions for λ,R and Θ from the previous problem are
A) λ=n2,R=rn,Θ=cos(nθ) ,n=1,2,3,… B) λ=n2,R=rn,Θ=sin(nθ) ,n=1,2,3,… C) λ=n2,R=rn,Θ=sin(nθ) ,n=0,1,2,… D) λ=n,R=rn,Θ=sin(nθ) ,n=1,2,3,… E) λ=n,R=rn,Θ=cos(nθ) ,n=1,2,3,…
Correct Answer:
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