An electron (m_e = 9.11* 10^-31 kg) traveling with a velocity of 1.1 *10⁶ m/s has a
De Broglie wavelength of approximately

Question

An electron (m_e = 9.11* 10^-31 kg) traveling with a velocity of 1.1 *10⁶ m/s has a De Broglie wavelength of approximately A) 0.66 nm B) 0.78 nm C) 0.89 nm D) 0.97 nm E) 1.2 nm

Quizplus · Accepted Answer

The de Broglie wavelength is given by the equation λ = h/p, where h is Planck's constant and p is the momentum of the particle. The momentum of the electron is given by p = mv, where m is the mass of the electron and v is its velocity. Substituting these values into the equation for the de Broglie wavelength, we get λ = h/mv = (6.626 x 10^-34 J s)/(9.11 x 10^-31 kg x 1.1 x 10^6 m/s) = 0.66 nm.

An Electron (Me = 9

An Electron (M_e = 9