The radius of the orbit of an electron moving with a speed of 10⁸ m/s perpendicular to a magnetic field of 5.0 $\times$10^-3 T is approximately A)1.1 m B)0.11 m C)0.34 m D)0.011 m E)8.9 m

Question

Quizplus · Accepted Answer

The correct answer is A because the radius of the orbit of an electron moving with a speed of 10^8 m/s perpendicular to a magnetic field of 5.0 x 10^-3 T is approximately 1.1 m. This can be calculated using the formula r = mv/qB, where r is the radius of the orbit, m is the mass of the electron, v is the speed of the electron, q is the charge of the electron, and B is the magnetic field strength.

The Radius of the Orbit of an Electron Moving with a Speed