If a sound of intensity I = 1.0  10^-6 W/m² falls on a detector of area A = 7.0 $\times$ 10^-5 m² (about the size of your eardrum),how much power is received by the detector? A)6.2 $\times$ 10^-14 W B)1.0 $\times$ 10^-6 W C)7.0 $\times$ 10^-11 W D)1.4 $\times$ 10^-2 W E)70 W

Question

Quizplus · Accepted Answer

The power received by the detector is calculated by multiplying the intensity of the sound by the area of the detector: $P = I \times A = 1.0 \times 10^{-6} \, \text{W/m}^2 \times 7.0 \times 10^{-5} \, \text{m}^2 = 7.0 \times 10^{-11} \, \text{W}$.

If a Sound of Intensity I = 1 ×\times× 10-5 M2 (About the Size of Your Eardrum),how Much Power

If a Sound of Intensity I = 1 $\times$ 10^-5 M² (About the Size of Your Eardrum),how Much Power