Find the inclination $\theta$ (in radians and degrees)of the line.Round your answer to four decimal places for radians and round your answer to one decimal places for degree. $7 x + 5 y = 0$
A) $\Theta \approx 2.2318 \text { radians } \approx 127.9 ^ { \circ }$
B) $\theta \approx 2.2318 \text { radians } \approx 128.9 ^ { \circ }$
C) $\theta \approx 2.2318 \text { radians } \approx 126.9 ^ { \circ }$
D) $\theta \approx 2.2318 \text { radians } \approx 129.9 ^ { \circ }$
E) $\theta \approx 2.2318 \text { radians } \approx 125.9 ^ { \circ }$

Question

Find the inclination $\theta$ (in radians and degrees)of the line.Round your answer to four decimal places for radians and round your answer to one decimal places for degree.​ $7 x + 5 y = 0$ ​
A)​ $\Theta \approx 2.2318 \text { radians } \approx 127.9 ^ { \circ }$
B) $\theta \approx 2.2318 \text { radians } \approx 128.9 ^ { \circ }$
C) $\theta \approx 2.2318 \text { radians } \approx 126.9 ^ { \circ }$
D) $\theta \approx 2.2318 \text { radians } \approx 129.9 ^ { \circ }$
E) $\theta \approx 2.2318 \text { radians } \approx 125.9 ^ { \circ }$

Quizplus · Accepted Answer

The inclination $\theta$ of a line with the equation $7x + 5y = 0$ can be found by converting it into slope-intercept form $y = mx + b$ to find the slope $m$, where $m = \tan(\theta)$. Rearranging $7x + 5y = 0$ gives $y = -\frac{7}{5}x$, so $m = -\frac{7}{5}$. The arctan of $-\frac{7}{5}$ gives the angle in radians, which is approximately $2.2318$ radians. Converting this to degrees by multiplying by $\frac{180}{\pi}$ gives approximately $127.9^\circ$.

Find the Inclination θ\thetaθ (In Radians and Degrees)of the Line 7x+5y=07 x + 5 y = 07x+5y=0

Find the Inclination $\theta$ (In Radians and Degrees)of the Line $7 x + 5 y = 0$