Find the center,vertices and foci of the hyperbola. $21 x ^ { 2 } - 5 y ^ { 2 } = 105$
A)Center: (0,0) Vertices: (0,0)
Foci: $( \sqrt { 21 } , 0 )$
B)Center: (0,0) Vertices: $( 0 , \pm \sqrt { 5 } )$
Foci: $( \pm \sqrt { 26 } , 0 )$
C)Center: (0,0) Vertices: $( \pm \sqrt { 5 } , 0 )$
Foci: $( \pm \sqrt { 26 } , 0 )$
D)Center: (0,0) Vertices: $( - \sqrt { 5 } , 0 )$
Foci: $( \pm \sqrt { 26 } , 0 )$
E)Center: (0,0) Vertices: $$( 0 , \pm \sqrt { 5 } )$$
Foci: $( 0 , \pm \sqrt { 26 } )$

Question

Find the center,vertices and foci of the hyperbola.​ $21 x ^ { 2 } - 5 y ^ { 2 } = 105$ ​
A)Center: (0,0) Vertices: (0,0)
Foci: $( \sqrt { 21 } , 0 )$
B)Center: (0,0) Vertices: $( 0 , \pm \sqrt { 5 } )$
Foci: $( \pm \sqrt { 26 } , 0 )$
C)Center: (0,0) Vertices: $( \pm \sqrt { 5 } , 0 )$
Foci: $( \pm \sqrt { 26 } , 0 )$
D)Center: (0,0) Vertices: $( - \sqrt { 5 } , 0 )$
Foci: $( \pm \sqrt { 26 } , 0 )$
E)Center: (0,0) Vertices: $$( 0 , \pm \sqrt { 5 } )$$
Foci: $( 0 , \pm \sqrt { 26 } )$

Quizplus · Accepted Answer

The equation of the hyperbola is $\frac{x^2}{5} - \frac{y^2}{21} = 1$, which is centered at (0,0) with vertices at $( \pm \sqrt{5}, 0 )$ and foci at $( \pm \sqrt{26}, 0 )$.

Find the Center,vertices and Foci of the Hyperbola 21x2−5y2=10521 x ^ { 2 } - 5 y ^ { 2 } = 10521x2−5y2=105

Find the Center,vertices and Foci of the Hyperbola $21 x ^ { 2 } - 5 y ^ { 2 } = 105$