Find all real value of x such that f (x)= 0. $$f ( x ) = \frac { - 9 x + 8 } { 5 }$$
A)x = $\frac { 8 } { 9 }$
B)x = $\frac { 8 } { 45 }$
C)x = ± $\frac { 8 } { 9 }$
D)x = $- \frac { 8 } { 9 }$
E)x = ± $\frac { 8 } { 45 }$

Question

Quizplus · Accepted Answer

To find the value of $x$ for which $f(x) = 0$, set the function equal to zero and solve for $x$: $$0 = \frac{-9x + 8}{5}$$ Multiplying both sides by 5 to eliminate the denominator gives: $$0 = -9x + 8$$ Adding $9x$ to both sides and then dividing by 9 gives: $$x = \frac{8}{9}$$

Find All Real Value of X Such That F (X)= f(x)=−9x+85f ( x ) = \frac { - 9 x + 8 } { 5 }f(x)=5−9x+8​

Find All Real Value of X Such That F (X)= $f ( x ) = \frac { - 9 x + 8 } { 5 }$