Let f (x)= 2x + 1,g(x)= 3x - 2.Find the function. $( f - g ) ( x )$
A) $( f - g ) ( x ) = \frac { 2 x + 1 } { 3 x - 2 }$
B) $( f - g ) ( x ) = 3 - x$
C) $( f - g ) ( x ) = 6 x ^ { 2 } - x - 2$
D) $( f - g ) ( x ) = 5 x - 1$
E)none of the above

Question

Let f (x)= 2x + 1,g(x)= 3x - 2.Find the function.​ $( f - g ) ( x )$ ​
A) $( f - g ) ( x ) = \frac { 2 x + 1 } { 3 x - 2 }$
B) $( f - g ) ( x ) = 3 - x$
C) $( f - g ) ( x ) = 6 x ^ { 2 } - x - 2$
D) $( f - g ) ( x ) = 5 x - 1$
E)none of the above

Quizplus · Accepted Answer

The function is f(g(x)), which means we need to substitute g(x) into f(x).

f(g(x)) = f(3x - 2) 
= 2(3x - 2) + 1 
= 6x - 3

Therefore, the function is 6x - 3 which matches with option B.

Let F (X)= 2x + 1,g(x)= 3x - 2 (f−g)(x)( f - g ) ( x )(f−g)(x)

Let F (X)= 2x + 1,g(x)= 3x - 2 $( f - g ) ( x )$