Write the logarithmic equation in exponential form. $\ln \left( \frac { 1 } { 7 } \right) = - 1.946 \ldots$
A) $e ^ { 1.946 ... } = - \frac { 1 } { 7 }$
B) $e ^ { 1.946 \ldots } = \frac { 1 } { 7 }$
C) $e ^ { - 1.946 \ldots } = 7$
D) $e ^ { - 1.946 \ldots } = \frac { 1 } { 7 }$
E) $e ^ { - 1.946 \ldots } = - \frac { 1 } { 7 }$

Question

Write the logarithmic equation in exponential form.​ $\ln \left( \frac { 1 } { 7 } \right) = - 1.946 \ldots$ ​
A) $e ^ { 1.946 ... } = - \frac { 1 } { 7 }$
B) $e ^ { 1.946 \ldots } = \frac { 1 } { 7 }$
C) $e ^ { - 1.946 \ldots } = 7$
D) $e ^ { - 1.946 \ldots } = \frac { 1 } { 7 }$
E) $e ^ { - 1.946 \ldots } = - \frac { 1 } { 7 }$

Quizplus · Accepted Answer

The logarithmic equation in exponential form would be: $$\log_{16}(256)=4$$ This can be rewritten as: $$16^4=256$$ Therefore, the choice with 62ac in the fourth group of digits represents the exponent 4 in hexadecimal form.

Write the Logarithmic Equation in Exponential Form ln⁡(17)=−1.946…\ln \left( \frac { 1 } { 7 } \right) = - 1.946 \ldotsln(71​)=−1.946…

Write the Logarithmic Equation in Exponential Form $\ln \left( \frac { 1 } { 7 } \right) = - 1.946 \ldots$