Rewrite the logarithm log₆ 412 in terms of the common logarithm (base 10). A)log 6 log 412 B) $\frac { \log 412 } { \log 6 }$ C) $\frac { \log 6 } { \log 412 }$ D)log 412 E) $\frac { \log 412 } { \log _ { 6 } 10 }$

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Quizplus · Accepted Answer

The change of base formula for logarithms states that $\log_b a = \frac{\log_k a}{\log_k b}$, where $k$ is the new base. Applying this formula to convert $\log_6 412$ into a common logarithm (base 10), we get $\frac{\log 412}{\log 6}$.

Rewrite the Logarithm Log6 412 in Terms of the Common log⁡412log⁡6\frac { \log 412 } { \log 6 }log6log412​

Rewrite the Logarithm Log₆ 412 in Terms of the Common $\frac { \log 412 } { \log 6 }$