When tuning a piano,a technician strikes a tuning fork for the A above middle C and sets up a wave motion that can be approximated by
Y = 0.001 sin 850πt,

Where t is the time (in seconds).

The frequency is given by f = 1 / p.What is the frequency of the note?

A)85 cycles/sec
B) $$\frac { 1 } { 425 }$$ cycles/sec
C) $$\frac { 1 } { 850 }$$ cycles/sec
D)850 cycles/sec
E)425 cycles/sec

Question

When tuning a piano,a technician strikes a tuning fork for the A above middle C and sets up a wave motion that can be approximated by ​
Y = 0.001 sin 850πt,
​
Where t is the time (in seconds).
​
The frequency is given by f = 1 / p.What is the frequency of the note?
​
A)85 cycles/sec
B) $$\frac { 1 } { 425 }$$ cycles/sec
C) $$\frac { 1 } { 850 }$$ cycles/sec
D)850 cycles/sec
E)425 cycles/sec

Quizplus · Accepted Answer

The frequency of the wave motion can be determined from the equation $Y = 0.001 \sin 850\pi t$. The general form of a wave equation is $Y = A \sin(2\pi ft)$, where $f$ is the frequency. Comparing the given equation to the general form, $2\pi f = 850\pi$. Solving for $f$ gives $f = \frac{850\pi}{2\pi} = 425$ cycles/sec.

When Tuning a Piano,a Technician Strikes a Tuning Fork for the a Above