Use an inverse function to write θ as a function of x.
A) $\theta = \arctan \frac { \sqrt { x ^ { 2 } - 9 } } { 3 }$
B) $\theta = \arctan \frac { 3 } { x }$
C) $\theta = \arctan \frac { 3 \pi } { x }$
D) $\theta = \arctan \frac { \sqrt { x ^ { 2 } + 9 } } { 3 }$
E) $\theta = \arctan \frac { x } { 3 }$

Question

Use an inverse function to write θ as a function of x. 
A) $\theta = \arctan \frac { \sqrt { x ^ { 2 } - 9 } } { 3 }$ 
B) $\theta = \arctan \frac { 3 } { x }$ 
C) $\theta = \arctan \frac { 3 \pi } { x }$ 
D) $\theta = \arctan \frac { \sqrt { x ^ { 2 } + 9 } } { 3 }$ 
E) $\theta = \arctan \frac { x } { 3 }$

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The Answer of Use an inverse function to write θ as a function of x. 
A) $\theta = \arctan \frac { \sqrt { x ^ { 2 } - 9 } } { 3 }$ 
B) $\theta = \arctan \frac { 3 } { x }$ 
C) $\theta = \arctan \frac { 3 \pi } { x }$ 
D) $\theta = \arctan \frac { \sqrt { x ^ { 2 } + 9 } } { 3 }$ 
E) $\theta = \arctan \frac { x } { 3 }$

Use an Inverse Function to Write θ as a Function θ=arctan⁡x2−93\theta = \arctan \frac { \sqrt { x ^ { 2 } - 9 } } { 3 }θ=arctan3x2−9​​

Use an Inverse Function to Write θ as a Function $\theta = \arctan \frac { \sqrt { x ^ { 2 } - 9 } } { 3 }$